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Multiple Choice

Voltage rise can be reduced by using larger wire sizes, reducing the microinverter quantity or by center feeding AC branch circuits.

Voltage rise on an AC feed is driven by the amount of backfed current and the impedance of the conductors carrying that current. The key idea is V = I × Z (the voltage change along the line equals the current times the line’s impedance). If you lower the current on the feeder, or decrease the impedance that current has to travel through, the voltage rise is reduced. Using larger wire sizes reduces the conductor’s resistance and reactance, so for the same amount of backfeed current, the voltage increase along the feeder is smaller. Reducing the number of microinverters lowers the total backfeed current on that feeder, which directly cuts the voltage rise. Center feeding the AC branch circuits splits the load and backfeed more evenly, so no single segment carries the full current, reducing the peak voltage rise on any one branch. In short, all three approaches reduce the I × Z effect that causes voltage rise, making the option true.

Voltage rise on an AC feed is driven by the amount of backfed current and the impedance of the conductors carrying that current. The key idea is V = I × Z (the voltage change along the line equals the current times the line’s impedance). If you lower the current on the feeder, or decrease the impedance that current has to travel through, the voltage rise is reduced.

Using larger wire sizes reduces the conductor’s resistance and reactance, so for the same amount of backfeed current, the voltage increase along the feeder is smaller. Reducing the number of microinverters lowers the total backfeed current on that feeder, which directly cuts the voltage rise. Center feeding the AC branch circuits splits the load and backfeed more evenly, so no single segment carries the full current, reducing the peak voltage rise on any one branch.

In short, all three approaches reduce the I × Z effect that causes voltage rise, making the option true.